3x^2+3x+2=20

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Solution for 3x^2+3x+2=20 equation:


Simplifying
3x2 + 3x + 2 = 20

Reorder the terms:
2 + 3x + 3x2 = 20

Solving
2 + 3x + 3x2 = 20

Solving for variable 'x'.

Reorder the terms:
2 + -20 + 3x + 3x2 = 20 + -20

Combine like terms: 2 + -20 = -18
-18 + 3x + 3x2 = 20 + -20

Combine like terms: 20 + -20 = 0
-18 + 3x + 3x2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(-6 + x + x2) = 0

Factor a trinomial.
3((-3 + -1x)(2 + -1x)) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(-3 + -1x)' equal to zero and attempt to solve: Simplifying -3 + -1x = 0 Solving -3 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1x = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1x = 0 + 3 -1x = 0 + 3 Combine like terms: 0 + 3 = 3 -1x = 3 Divide each side by '-1'. x = -3 Simplifying x = -3

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {-3, 2}

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